Armchair over the history of the year. Dates ege on history

In about mae month, options are published. Eg early Period. The purpose of the publication is to grant additional opportunities to prepare for the exam.

Early EEH EEGERS 2017

Thing	Download the starting option
History 2017 year	iStoriya.
2016	vARIANT EGE 2016.
2015	variant EGE 2015.

Published by one version of KIM used for eMEE early period of 2017.

Changes in the structure of Kim on history compared with 2016:

No changes in structure and content.

The maximum score is changed for performing tasks 3 and 8 (2 points instead of 1). Improved wording of task 25 and the criteria for its estimation.

All tasks (in brackets - including the evaluation criteria for the composition) - 25 (31);

of these, by type of task:

with a brief answer - 19;

with an expanded answer - 6 (12);

in terms of complexity (including the criteria for the evaluation of the composition): b - 16; P - 8; AT 7.

Maximum primary score For work - 55.

The total time of work is 235 minutes.

Structure Kim Ege 2017 on History

Each version of the examination work consists of two parts and includes 25 tasks that differ in the form and level of complexity.

Part 1 contains 19 tasks with a brief answer. In the examination work proposed the following types of tasks with a brief answer:
- tasks for choosing and recording the correct answers from the proposed list of responses;

- tasks for determining the sequence of data of these elements;

- tasks for establishing conformity of items, data in several information series;

- Quests on the definition of specified features and recording in the form of a word (phrase) of the term, names, name, century, year, etc.

The answer to the tasks of part 1 is given by the corresponding record in the form of a sequence of numbers recorded without spaces and other separators; the words; phrases (also recorded without spaces and other separators).

Part 2 contains 6 tasks with an expanded response that detects and evaluating the development of graduates of various complex skills.
Tasks 20-22 are a set of tasks related to the analysis of the historical source (conducting the source attribution; extraction
information; Attraction historical knowledge To analyze the problems of the source, the position of the author).

Tasks 23-25 \u200b\u200bare associated with the use of the techniques of causal, structural and functional, temporary and spatial analysis for studying historical processes and phenomena. Task 23 is associated with an analysis of any historical problem, situations. Task 24 - Analysis of historical versions and assessments, the argument of different points of view with the involvement of the knowledge of the course. Task 25 implies writing historical essay. Task 25 Alternative: The graduate has the opportunity to choose one of the three periods of the history of Russia and demonstrate their knowledge and skills on the most familiar historical material. Task 25 is estimated on the criteria system.

The exam on history is usually a little more than 5 percent of students who scored high scores. Two two times more than two times.

It is noted that not everyone can work with maps and actual material. Schoolchildren are often mistaken when answering questions about the Great Patriotic War. Pupils do not always understand the difference between it and the Second World War.

Before exams, it is recommended to repeat the dates, refresh in the memory of the name of the commander, heroes, public figures. So, on the exam, 2016 about 20 percent of graduates wrote that hero Soviet Union Is the fighter - a diversionist executed by the fascists in 1941 Lydia Ruslanov, and not Zoya Kosmodemyanskaya. There were those who marchal Alexander Vasilevsky sent to the battle to the Chesmen Bay of 1770, while he was the head of the General Staff during the Great Patriotic War, commanded the 3rd Belarusian Front, led Konigsberg's assault.

Starting period one state exam 2017 passed without failures in calm mode, the head said Federal Service According to the supervision in the field of education and science, Sergey Kravtsov, summing up the early exams during the Moscow International Education Salon (MMSO).

"The early period of the EGE this year was calm, without failures. There are no serious violations and leaks of examinations, "said Sergey Kravtsov.

The early period of the exam was held from March 23 to April 14. The exams handed over 26.5 thousand participants, it is about 10 thousand more than last year. Basically, graduates of past years wrote, who wished to improve their result on this or that object.

Early period exams handed over in all subjects of the Russian Federation, except for Chukotka autonomous District. To conduct them, 275 examinations (PPE) were involved.

In all points of the early wave, video surveillance in online mode was carried out, using the printing technologies of control measuring materials (KIM) and scanning forms of responses of participants in the audiences. In the monitoring of the course of examinations, the employees of the Rosobrnadzor submitted by him, about 1,000 students of regional universities that became public observers, and more than 300 online observers.

The most popular with the examination of the exam in the start period were mandatory objects, Russian and mathematics, as well as social studies. More than 20% of participants chose history, exams in physics and biology - over 16% of the participants in the early period, chemistry - 11%.

Sergey Kravtsov said that this year the number of participants in the early period of the exam was reduced, which could not overcome the minimum threshold of points. According to him, the analysis of labels made on online observer exams continues. According to the results of the analysis will be clarified total number violators of the order of the exam at the early stage.

Option number 1489759.

Ege - 2017. Armchair Wave

When you execute tasks with a short response, enter the number in the response field, which corresponds to the correct answer number, or the number, word, the sequence of letters (words) or numbers. The answer should be recorded without spaces and any additional characters. Answers to Jobs 1-19 is a sequence of numbers, digit or word (phrase). The names of Russian sovereign should write only letters.

If the option is specified by the teacher, you can enter or download answers to the tasks with a detailed answer. The teacher will see the results of tasks with a brief response and will be able to evaluate the downloaded responses to the tasks with the detailed answer. The scores exhibited by the teacher will be displayed in your statistics.

Printing and copying version in MS Word

Place B. chronological sequence historical events. Record the numbers that are indicated by historical events, in the correct sequence in the table.

1) rebellion under the leadership of K. A. Bulavin

2) the first mention of Moscow in the Ipatiev Chronicle

3) defeat England invincible Armada

Answer:

Set the match between events and years: to each position of the first column, select the appropriate position from the second column.

Answer:

Below is a list of terms (titles). All of them, with the exception of two, belong to the events (phenomena) of Russia of Russia XVIII century.

1) Palace coup

2) Slavophila

3) Seating Peasants

4) Favoritism

5) redemption payments

6) College

Find and write down the sequence numbers of terms (names) relating to another historical period.

Answer:

Specify the term about which it is spent.

The name of the territorial community in Ancient Russia, whose members carried the collective responsibility for murders and thefts committed within the borders of the community; Mentioned in Russian truth.

Answer:

Ni-Vi-Thie-Social Between Pro-Cesse-Ca-Mi (Jav-Le Ni-Mi, Co-Ti-Yi) and Toba-Mi, From-no-soup-sig, to these pro-Cesse-Himself (Jav-Le Ni-Yam, Coh-Ti-Yam): Each in the province of per-in-go Pole under-BE-Ri-Thu-OT-Roma-Yuchno in the WTO Pole.

Pro-Cesse (Jav-lesya, CO-would be

FACTS

A) the externalist in the Li-Ti-ka of the USSR in the PE-Ri-OD-Co-Water-ON N. S. Khrushcheva

B) Ex-nya Li-Ti-Ka Rus-Zey

C) Rus-Ski-Tu-Rec-Kai War 1787-1791.

D) Damn it time in Ros-Siia

1) Battle on the river She-Lo

2) CO-ZDA or-ha-ni-nation of the Var-Shav-Kho-th-th

3) input of co-vet troops in af-ha-ni-camp

4) Singo-Nee-Nie

5) Lip-d-Mit-Riya II campaign at Moscow

6) the campaign of Ki-Ev-Ku Prince Oleg on Vi-Zan

In the answer numbers, placing them in a row-ke, the beech-to you:

BUT	B.	IN	G.

Answer:

Major-Vi-Thrag-T-Mi-T-Ri-Thrag-Men-Ta-Ni-Roshki-Cups and their short-cycle ha-cancer -Ri-ka-mi: to each frag-men --th, aware of the book-chen-but-mu, under-bibe-th, two co-from-vet -Un ha-cancer-te-ri-ki, obvious digit-ray.

Frag-Men-You Is-Cop-Nich

A) "On the Way, the year after the WHO is nesting with in the BE-Doya Prince ... again at the time [not-at-Ya-Te-Lee] from the per-pond country and In fact, the city on the ground of the prince. The prince ... I walked the city of them and the city of them to OS-no-va, and they themselves - alone in ordinary forces, walked with them, and other, in Mi-lo - Wav, from-Pu-styl, for was without Mer-Mi-Lo-Steve.

On the three year ... at which the Germans went to the muddy lake, and they met their prince, and from now-Vil-Xia to battle, and they went to each other, and Krym Elk Lake People's Miracle Monthly and Druzhi and New ... "

B) "In all the same Go-Su-Dar-Sov-Soo-Su-Dar-Sum-Say-Dar-Say-Sha, the Ta-Co-Noe Du-co-harm under Moscow and -Be-Lee and Pla-Ka-Li, and Cre-Sticks are not a go-de-de-de-de, but no one could in mind. From all the same grads in Sing Mr. Grad, in the bottom of New-go-de, the same-rod-tsy ... on-chai, cape-pour, as if at a memorial moss Kov-Ski-Mou-Su-Dar. One of them, the same-go-decen, having a Yu-Yu Tor-gov-Liu Meat, Goat Minin, Re-Co-Moy Su-Ho-Hands, Whether in All People: "Will we have inherent in the Mosh Mos-Kov-North-Su-Su-Dar-Sovie, and Io, we are not the same-lem-tee of our" ... The Rod-Tzam also all his word of love was, and in Du-Ma-whether they in order to beat the brow to the prince of Dmitri Mi-Hai-Lo-Chu ... Poe Cher-Koo A-and-mand-like AR-Cheri-Mand-Ri-Tu Fe-o-du, yes, of all the ranks of all the ray of people. "

CHARACTERISTICS

1) OPI-Si-Va-Edom CO-would be pro-Iso in the XVI century.

2) Prince, UPO-me-well-in-friend, was a par-nom-com from-bouquet.

3) Prince, UPO-Mi-Nu in Otrv-Ke, in Lou-Chill Pro-Zvi-Zepy Donskoy.

4) OPI-Si-Va-Est CO-would be pro-Iso in the XIII century.

5) OPI-Si-Va-Edom CO-would be pro-Iso in the XVII century.

6) Prince, UPO-Mi-Nu in Otrv-Ke, in Lu-Chil Pro-Zvi-Sky-Sky.

Frag cop		Frag-ment b

Answer:

Which of the PE-RUN-Lena CO-would be pro-Iso in the PE-Ri-Od-Co-Water-One of the USSR N. S. Khrushcheva? You are-be-Ri-Thy three of the Tia and in-Pi-Shi-those in Tab Li-Tsu numbers, under the sorts they are decorated.

1) input of co-vet troops in af-ha-ni-camp

2) on-Cha-Lo Kam-Paradi by Kos-Mo-Li-Tiz-Ma in the USSR

3) Ras-arrows of the de Mon-Stroy-ration of Ra-Bo-Chih in but-in-Cher-Kas-Ske

4) LIK-VI-DAGE MA-TIN-NO-TOMOBOV

5) Li-Ba-Ra-Lee

6) Ka-Rib-Sky Cree

Answer:

Fill in passing in these proposals using the list of missed items below: for each sentence, indicated by the letter and containing the skip, select the number of the desired item.

A) Soviet intelligence officer, partisans, who, issuing himself for a German officer in Rivne and Lviv, mined valuable information, destroyed several prominent Hitlerians, - ____________.

B) the operation of the Red Army "Uranus" began in ____________.

C) During the Great Patriotic War, the fascists failed to capture the city _____________.

Missed elements:

2) Yu. B. Levitan

6) N. I. Kuznetsov

BUT	B.	IN

Answer:

Set the correspondence between events (processes, phenomena) and their participants: To each position of the first column, select the corresponding position from the second column.

Write the numbers in response by placing them in order corresponding to the letters:

BUT	B.	IN	G.

Answer:

Read the passage from the resolution adopted at the International Conference, and indicate the name of the chairman of the Soviet government during the period when this conference was held.

"Allied lenders states ... cannot accept any obligations regarding claims declared by the Soviet government.

In view of, however, the difficult economic situation of Russia, the lenders states are inclined to reduce Russia's military debt towards them as a percentage of which should be determined subsequently. The nation presented in Genoa tend to take into account not only the question of delaying the payment of current interest, but also on the deferment of the payment of part of expired or overdue interest. "

Answer:

Fill out the empty cell cells using the list of missed elements below: for each pass indicated by the letter, select the number of the desired item.

Missed elements:

1) the beginning of the Board in Kiev Prince Vladimir Svyatoslavich

2) the beginning of the crusades

4) Education of the Sacred Roman Empire

6) Camping Khan Tokhtamysh to Moscow

7) "Nice Revolution" in England

9) Joining the Moscow State Tver

Write the numbers in response by placing them in order corresponding to the letters:

A.	B.	IN	G.	D.	E.

Answer:

Read the excerpt from the chronicle.

"In the year 6370. and expelled Varyagov for the sea, and did not give them Dani, and they began to own themselves, and did not have truth among them, and they had a rode for the genus, and they had a craftsman, and began to fight with each other. And they said, "We are looking for the prince themselves who would have owned and ruined for a number and by law." Let's go for the sea to Varyags, to Russia. Those whocks were called Russia as others are called Swedes, and other - Normans and Angles, and even other - goths, like these. They said Rus Chud, Slavs, Crivichi and the whole: "Our Land is great and is abundant, but there is no order in it. Come to the princes and possess us." And three brothers were chosen with their childbirth, and took with them all of Russia, and came first of all to the Slavs. And put the city of Ladoga. And the senior sat down in Ladoga, and the other - Sineus - on a white lake, and the third - Trourway - in Izborsk. And the Russian land was nosed from those whirlwinds. Two years later, Sineus and brother of his Trourway died. And he accepted all the power of one ... [Prince], and came to Ilman, and put the city over the Volkhov ... and I sat down here, and I began to hand out my parish and to put the city. "

Using an excerpt and knowledge of history, select three faithful judgments in the list.

Figures indicate in ascending order.

1) In the passage, the Eastern Slavic tribal union, which occupied the territory of the Middle River of the Dnipro river, with the center in Kiev was mentioned.

3) In the passage, the Finno-Ugric tribes mentioned.

4) In the passage, the name of the tribal union eastern Slavs.I raised the uprising, during which the son of the Prince mentioned in the text was killed.

6) The excerpt describes an event dating from modern chores 862.

Answer:

In-Paul-Ni-Those in the pre-Lo-Nii: "CO-would be, obviously in the scheme, pro-iso-walked in you-chase de-rust -The ____________________ year. " Answer in Pi-Shi-Thom Society (CO-Che-Ni-Ey).

Answer:

Pow-residents are on the ranks of GO-RO, the overall-chen-but-go on the digital "4" scheme, in the PE-Ri-od, when the pro-Iso -This, reflected in the diagram.

Answer:

Specify the name of the city designated on the diagram of the number "2".

Answer:

What is the Scent De-Say, from-no-soup-e-smi to a given scheme, is a sudent version? You are the three sougens of six pre-lobs. In the Pi-Shi-te, in the tab-li-tsu numbers, under which they are decorated.

Figures indicate in the order of WHO Rasp.

1) the city, obviously in the digital digital scheme "3", in the one-hundred-hour time in accordance with Ros-Siia.

2) the city, oversea "5" in the digital diagram, was a strain from Fa-Shi-Stov Osse-New.

3) In the course of the bo-eday, obviously on the scheme of arrivals, the Kras-Naya Army Paul-no-Stew of the Others-Bo di-La Ho Vasya.

4) on the scheme of the action of the Action of the Krasovy Army during the opearance of the Bag-Ra-Ti-He.

5) on the scheme of the monitoring of the Action of the Krasovy Army during the in-time-no-pyrous opera-ration.

6) The city, obviously in the digital "1" scheme, was a strain from Fa-Shi-Stov in Ok-Tyab-re.

Answer:

Install the correspondence between cultural monuments and their brief characteristics: To each position of the first column, select the appropriate position from the second column.

Write the numbers in response by placing them in order corresponding to the letters:

BUT	B.	IN	G.

Answer:

What are the Sum-de-Dan-mint-noye-non-te -ham-in-si versions? You are the two sougu-de-five of the five pre-lob. In the Pi-Shi-te, in the tab-li-tsu numbers, under which they are decorated.

1) co-by-type, which-ro-mu in the provision-on Dan-Naya Mo-Na-Ta, pro-Iso less than a year before the excretion of But right in Ros-Siia.

2) on the Mo-Neu-Dar-Sum-Dar-Dar-Dar of the Organ, the institution-waiting Pet-rum I.

3) Isob-raised on the Mo-Ne-Thie-Siy-Syl-La-Ros-Tor-Lu-Chil about-Zvi-Ti-Shay.

4) Dan-Naya Mo-Na-Tu-Posh-on-year, when Pre-Zi-Den Ros-Sii was D. A. Med-Ve-vir.

5) You are the now-su-dar-darity posts in the PE-ROM-OR-RA-RA, isob-raised on Mo-Neu, Ni-Ma Li A. H. Ben-Ken-Dorf and S. S. Uvan.

Answer:

Which of the cultural figures presented below were the contemporaries of the events, in memory of which this coin was released? In response, write down two figures that are designated by these cultural figures.

Answer:

Indicate up to half a century, the period to which this document. Specify tsarist dynasty, which was the ruler reflected in the document. Specify its successor.

From the petition tsar.

And led the sovereign, to choose in the cities of the nobles and from the Zemsky people, and led, sovereigns, our horses, to judge in the cities in their sovereign decree and on their sovereign underlying judicial book to you, soverees, from us, your keys , [annoying requests] was not, and we b, your chores, from Moscow Volokhta, did not dwell, and from Moscow all sorts of ranks strong people And from the monasteries, and from all of the authorities were not on sale, and so that we, the hills of yours, from their sale and violence did not die ... "

On the next page you will be asked to check them yourself.

What measures, carrying out girls waiting for from the king, are indicated in this passage? Specify any three measures.

Read the excerpt from the historical source and briefly answer questions 20-22. Answers suggest the use of information from the source, as well as the use of historical knowledge at the rate of the history of the corresponding period.

From the petition tsar.

"The merciful sovereign king and grand Duke Mikhail Fedorovich All Russia! Perhaps, of us, their horses, for the previous ones and blood for our poverty and torn, and for their state services, incessant by the eternal state salary, as it was with former sovereigns, and your sovereigns, a decree: led, sovereign, those urgent years to retain five years , and the peasants of our runaway and people led, sovereign, to us, holopas for their own, to give in scribe and separate books, And on our fortresses, so that our estates and faults are not launched, and the rest of the peasants and people because of us, your horses, did not come out, and so that we, your chores, serving your sovereign incessant service and paying your sovereign all sorts of grants, Broadcast did not died. And led the sovereign, for the authorities, and the monasteries, and in the Moscow all sorts of people in our runaway peasants and in the people and in the resentment to give us, the hills of their own, on them and on their princes and on the peasants the court in those cities in which , the sovereign, the time for us, your holopas, you have to be a sovereign to them.

Specify the name of the Code of laws adopted during the reign of the king's successor referred to in the document. Attracting historical knowledge, specify at least two establishments of this vault, determining the situation of the dependent categories of the country's population.

From the petition tsar.

"Merciful Sovereign King and Grand Duke Mikhailo Fedorovich All Russia! Perhaps, of us, their horses, for the previous ones and blood for our poverty and torn, and for their state services, incessant by the eternal state salary, as it was with former sovereigns, and your sovereigns, a decree: led, sovereign, those urgent years to retain five years , and the peasants of the runaway of our and people led, sovereign, we, holopams to give them on the scribe and on individual books, and on our fortresses, so that our estates and womb are not launched, and the rest would be peasants and people because of us, your horses , did not come out, and so that we, your chores, serving your sovereign incessant service and paying your sovereign all sorts of grants, did not died. And led the sovereign, for the authorities, and the monasteries, and in the Moscow all sorts of people in our runaway peasants and in the people and in the resentment to give us, the hills of their own, on them and on their princes and on the peasants the court in those cities in which , the sovereign, the time for us, your holopas, you have to be a sovereign to them.

1) 1054-1132;

The essay requires:

Specify at least two significant events (phenomena, processes) relating to this period of history;

Name two historical individuals whose activities are associated with these events (phenomena, processes), and, using knowledge of historical facts, characterize the roles of the personalities you mentioned in these events (phenomena, processes);

Attention!

When characterizing the role of each person named, it is necessary to indicate the specific actions of this person, to a large extent influenced the course and (or) the result of these events (processes, phenomena).

During the presentation, it is necessary to correctly use historical terms, concepts relating to this period.

Task solutions with a detailed answer are not automatically checked.

To perform tasks 1-3, use the following series of chemical elements. The answer in the tasks 1-3 is the sequence of numbers under which the chemical elements are indicated in this series.

1. S.
2. Na.
3. al
4. SI.
5. MG.

Task number 1

Determine, atoms of which of those specified in the number of elements are mainly containing one unpaired electron.

Answer: 23.

Explanation:

We write the electronic formula for each of these chemical elements and depicting the electronic graphic formula of the last electronic level:

1) S: 1S 2 2S 2 2P 6 3S 2 3P 4

2) NA: 1S 2 2S 2 2P 6 3S 1

3) AL: 1S 2 2S 2 2P 6 3S 2 3P 1

4) Si: 1S 2 2S 2 2P 6 3S 2 3P 2

5) MG: 1S 2 2S 2 2P 6 3S 2

Task number 2.

From those specified in a number of chemical elements, select three metal elements. Place the selected items in order of increasing reducing properties.

Write down in the response field of the selected items in the desired sequence.

Answer: 352.

Explanation:

In the main subgroups of the Mendeleev table, the metals are located under the diagonal of Bor-Astat, as well as in side subgroups. Thus, the metals from the specified list include Na, Al and Mg.

Metal and, therefore, the reduction properties of the elements increase when moving to the left at the period and down the subgroup. Thus, the metal properties of the metals listed above are increasing in the series Al, Mg, Na

Task number 3.

From among those indicated in a number of items, select two elements that in compound with oxygen exhibit the degree of oxidation +4.

Record in the response field of the selected items.

Answer: 14.

Explanation:

The main degrees of oxidation of elements from the submitted list in complex substances:

Sulfur - "-2", "+4" and "+6"

Sodium Na - "+1" (only)

Aluminum Al - "+3" (only)

Si - "-4", "+4"

Magnesium MG - "+2" (only)

Task number 4.

From the proposed list of substances, select two substances in which ionic chemical bond is present.

1. KCL.
2. KNO 3.
3. H 3 BO 3
4. H 2 SO 4
5. PCL 3.

Answer: 12.

Explanation:

It is possible to determine the presence of an ionic type of communication in compound in the overwhelming majority of cases, it is possible for the composition of its structural units at the same time the atoms of typical metal and the non-metal atoms are included.

Based on this criterion, the ion type of communication takes place in KCL and KNO 3 connections.

In addition to the above feature, the presence of ion communication in the compound can be said if in its composition structural unit Contains ammonium cation (NH 4 +) or its organic analogs - alkylammonium cations RNH 3 +, dialkilamion R 2 NH 2 +, trialkimmonium R 3 NH + and tetraalklammonium R 4 n +, where R is some hydrocarbon radical. For example, the ion type of communication takes place in compound (CH 3) 4 NCL between the cation (CH 3) 4 + and the CL chloride-ion.

Task number 5.

Set the correspondence between the formula of the substance and the class / group to which this substance belongs: to each position indicated by the letter, select the appropriate position indicated by the number.

BUT	B.	IN

Answer: 241.

Explanation:

N 2 O 3 - Nemetal oxide. All non-metallic oxides besides N 2 O, NO, SiO and CO are acidic.

Al 2 O 3 - metal oxide into oxidation degree +3. Metal oxides into oxidation degree + 3, + 4, as well as BEO, ZNO, SNO and PBO, are amphoter.

HCLO 4 is a typical source representative, because During dissociation in aqueous solution, only n + cations are formed from the cations:

HCLO 4 \u003d H + + CLO 4 -

Task number 6.

From the proposed list of substances, select two substances with each of which is interacting with zinc.

1) nitric acid (r-p)

2) iron hydroxide (II)

3) magnesium sulfate (rr)

4) sodium hydroxide (r-p)

5) Aluminum chloride (R-R)

Write down in the response field of the selected substances.

Answer: 14.

Explanation:

1) nitric acid is a strong oxidizing agent and reacts with all metals besides platinum and gold.

2) iron hydroxide (LL) is an insoluble base. With insoluble hydroxides, the metals do not react at all, and with soluble (alkalis), only three metal react - BE, Zn, Al.

3) magnesium sulfate - salt of more active metal than zinc, and therefore the reaction does not flow.

4) sodium hydroxide - alkali (soluble metal hydroxide). Alits from metals only be, zn, al.

5) AlCl 3 - salt more active than zinc metal, i.e. The reaction is impossible.

Task number 7.

From the proposed list of substances, select two oxide that react with water.

1. Bao.
2. Cuo.
3. No.
4. SO 3.
5. PBO 2.

Write down in the response field of the selected substances.

Answer: 14.

Explanation:

From oxides with water, only alkaline and alkaline earth metal oxides react, as well as all acid oxides except SiO 2.

Thus, the options for answers 1 and 4 are suitable:

Bao + H 2 O \u003d BA (OH) 2

SO 3 + H 2 O \u003d H 2 SO 4

Task number 8.

1) Bromomopod

3) sodium nitrate

4) Sulfur Oxide (IV)

5) aluminum chloride

Write in the table selected numbers under the appropriate letters.

Answer: 52.

Explanation:

Salts among these substances are only sodium nitrate and aluminum chloride. All nitrates, as well as sodium soluble salts, due to the precipitate, sodium nitrate cannot give in principle with any of the reagents. Therefore, salt X can only be aluminum chloride.

A common error among the exams in chemistry is not understanding that in an aqueous solution of ammonia forms a weak base - ammonium hydroxide due to the reaction flow:

NH 3 + H 2 O<=> NH 4 Oh.

In this regard, an aqueous solution of ammonia gives a precipitate when mixed with solutions of metals salts forming insoluble hydroxides:

3NH 3 + 3H 2 O + AlCl 3 \u003d Al (OH) 3 + 3NH 4 Cl

Task number 9.

In a given scheme of transformations

Cu. X.\u003e CUCL 2. Y.\u003e Cui.

substances X and Y are:

1. Agi.
2. I 2.
3. Cl 2.
4. HCL.
5. Ki.

Answer: 35.

Explanation:

Copper - metal, located in a row of activity to the right of hydrogen, i.e. Does not react with acids (except H 2 SO 4 (conc.) and HNO 3). Thus, the formation of copper chloride (LL) is possible in our case only when reactions with chlorine:

Cu + Cl 2 \u003d CUCL 2

Iodide ions (I -) cannot coexist in one solution with bivalent copper ions, because oxidize them:

Cu 2+ + 3i - \u003d Cui + I 2

Task number 10.

Set the correspondence between the reaction equation and the substance-oxidizing agent in this reaction: to each position indicated by the letter, select the corresponding position indicated by the number.

Answer: 1433.

Explanation:

The oxidizer in the reaction is the substance that contains an element that reduces its oxidation degree

Task number 11.

Install the correspondence between the formula of the substance and reagents, with each of which this substance can interact: to each position indicated by the letter, select the corresponding position indicated by the number.

Answer: 1215.

Explanation:

A) Cu (NO 3) 2 + NaOH and CU (NO 3) 2 + Ba (OH) 2 - similar interactions. Salt with metal hydroxide reacts if the source substances are soluble, and in the products there is a precipitate, gas or a slightly subsorative substance. And for the first and for the second reaction, both requirements are performed:

Cu (NO 3) 2 + 2NAOH \u003d 2Nano 3 + Cu (OH) 2 ↓

Cu (NO 3) 2 + BA (OH) 2 \u003d Na (NO 3) 2 + Cu (OH) 2 ↓

Cu (NO 3) 2 + Mg - salt with metal reacts if the free metal is more active in the composition of the salt. Magnesium in a row of activity is located left copper, which indicates its greater activity, therefore, the reaction proceeds:

Cu (NO 3) 2 + Mg \u003d Mg (NO 3) 2 + Cu

B) Al (OH) 3 - metal hydroxide into the degree of oxidation +3. Metal hydroxides in the degree of oxidation + 3, + 4, as well as the exceptions of BE hydroxides BE (OH) 2 and Zn (OH) 2, are amphoter.

By definition, the amphoteric hydroxides are called those that react with alkali and almost all soluble acids. For this reason, you can immediately conclude that the answer option is suitable:

Al (OH) 3 + 3HCl \u003d AlCl 3 + 3H 2 O

Al (OH) 3 + LiOh (p-p) \u003d Li or Al (OH) 3 + LiOh (TV.) \u003d To \u003d\u003e Lialo 2 + 2H 2 O

2AL (OH) 3 + 3H 2 SO 4 \u003d Al 2 (SO 4) 3 + 6H 2 O

C) ZnCl 2 + NaOH and ZnCl 2 + Ba (OH) 2 - the interaction of the type "salt + hydroxide metal". The explanation is given in P.A.

ZnCl 2 + 2NAOH \u003d Zn (OH) 2 + 2NACL

ZnCl 2 + Ba (OH) 2 \u003d Zn (OH) 2 + BaCl 2

It should be noted that with an excess of NaOH and BA (OH) 2:

ZnCl 2 + 4NAOH \u003d Na 2 + 2NACL

ZnCl 2 + 2BA (OH) 2 \u003d BA + BACL 2

D) br 2, o 2 - strong oxidizers. Metals do not react only with silver, platinum, gold:

CU + BR 2 t ° \u003e Cubr 2.

2CU + O 2 t ° \u003e 2Cuo.

HNO 3 - Acid with strong oxidative propertiesbecause oxidizes not by hydrogen cations, but by the acid-forming element - nitrogen N +5. Reacts with all metals besides platinum and gold:

4HNO 3 (conc.) + Cu \u003d Cu (NO 3) 2 + 2NO 2 + 2H 2 O

8HNO 3 (RSS) + 3CU \u003d 3CU (NO 3) 2 + 2NO + 4H 2 O

Task number 12.

Set the correspondence between general formula The homologous series and the name of the substance belonging to this series: to each position indicated by the letter, select the corresponding position indicated by the number.

Write in the table selected numbers under the appropriate letters.

BUT	B.	IN

Answer: 231.

Explanation:

Task number 13.

From the proposed list of substances, select two substances that are isomers of cyclopentane.

1) 2-methylbutan

2) 1,2-dimethylcyclopropane

3) Penten-2

4) hexen-2

5) Cyclopenten

Write down in the response field of the selected substances.

Answer: 23.

Explanation:

Cyclopentane has a molecular formula C 5 H 10. We write the structural and molecular formulas listed in the condition

Name of substance	Structural formula	Molecular formula
cyclopentane		C 5 H 10
2-methylbutan
1,2-dimethylcyclopropan		C 5 H 10
		C 5 H 10

cyclopenten

Task number 14.

From the proposed list of substances, select two substances, each of which reacts with a solution of potassium permanganate.

1) methylbenzene.

2) Cyclohexane

3) methylpropan

Write down in the response field of the selected substances.

Answer: 15.

Explanation:

From hydrocarbons with an aqueous solution of potassium permanganate, those containing in their structural formula C \u003d C or C≡C of communication, as well as benzene homologs (except for benzene itself).

This is suitable methyl benzene and styrene.

Task number 15.

From the proposed list of substances, select two substances with which phenol interacts.

1) hydrochloric acid

2) sodium hydroxide

4) nitric acid

5) sodium sulfate

Write down in the response field of the selected substances.

Answer: 24.

Explanation:

Phenol has weak acid properties, pronounced more brightly than alcohols. For this reason, phenols are unlike alcohols with alkalis:

C 6 H 5 OH + NaOH \u003d C 6 H 5 ONA + H 2 O

Phenol contains in its molecule a hydroxyl group directly attached to the benzene ring. The hydroxy group is the first-kind orientant, that is, facilitates reactions of substitution in ortho and para-positions:

Task number 16.

From the proposed list of substances, select two substances that are subjected to hydrolysis.

1) Glucose

2) Sakhares

3) fructose

5) Stachmal

Write down in the response field of the selected substances.

Answer: 25.

Explanation:

All listed substances are carbohydrates. From hydrolysis of hydrolysis is not subject to monosaccharides. Glucose, fructose and ribosis are monosaccharides, sucrose - disaccharide, and starch - polysaccharide. Therefore, the hydrolysis is subjected from the specified list of sucrose and starch.

Task number 17.

The following scheme of the transformation of substances is given:

1,2-Diberomethane → X → Brometan → Y → Ethyl formate

Determine which of these substances are substances X and Y.

2) Ethanal

4) Chlorhetan

5) Acetylene

Record into the table number selected substances under the appropriate letters.

Task number 18.

Set the correspondence between the title of the starting material and the product, which is preferably formed when the interaction of this substance with bromine: to each position indicated by the letter, select the appropriate position indicated by the number.

Write in the table selected numbers under the appropriate letters.

BUT	B.	IN	G.

Answer: 2134.

Explanation:

Replacement at a secondary carbon atom flows to a greater extent than during primary. Thus, the main product of propane bromination is 2-bromopropane, and not 1-bromopropane:

Cyclohexane - cycloalkan with a cycle size of more than 4 carbon atoms. Cycloalkanes with a cycle size of more than 4 carbon atoms when interacting with halogens, react substitution with the cycle preservation:

Cyclopropin and cyclobutane - cycloalkanes with a minimum cycle size preferably enter the attachment reaction, accompanied by a cycle break:

The substitution of hydrogen atoms with a tertiary carbon atom occurs to a greater extent than when secondary and primary. Thus, the bromination of isobutan proceeds mainly as follows:

Task №19.

Install the correspondence between the reaction scheme and the organic matter, which is the product of this reaction: to each position indicated by the letter, select the corresponding position indicated by the number.

Write in the table selected numbers under the appropriate letters.

BUT	B.	IN	G.

Answer: 6134.

Explanation:

The heating of aldehydes with freshly fired copper hydroxide leads to the oxidation of the aldehyde group to carboxyl:

Aldehydes and ketones are reduced by hydrogen in the presence of nickel, platinum or palladium to alcohols:

Primary and secondary alcohols are oxidized by the hot Cuo to aldehydes and ketones, respectively:

Under the action of concentrated sulfuric acid on ethanol, when heated, two different products are possible. When heated to a temperature below, 140 OS is preferably intermolecular dehydration with the formation of diethyl ether, and when heated, more than 140 ° C is intramolecular, as a result of which ethylene is formed:

Task number 20.

From the proposed list of substances, select two substances, the response of the thermal decomposition of which is the redox.

1) aluminum nitrate

2) potassium bicarbonate

3) aluminum hydroxide

4) Ammonium carbonate

5) ammonium nitrate

Write down in the response field of the selected substances.

Answer: 15.

Explanation:

Oxidative and restores are called such reactions as a result of which chemical one or more chemical elements change their degree of oxidation.

The decomposition reactions are absolutely all nitrates relate to redox. Nitrates of metals from Mg to Cu inclusive decompose to metal oxide, nitrogen dioxide and molecular oxygen:

All metal bicarbonates decompose already with insignificant heating (60 o C) to metal carbonate, carbon dioxide and water. At the same time, changes in oxidation degrees does not occur:

Insoluble oxides decompose when heated. The reaction is not oxidative and reducing. No chemical element of the degree of oxidation as a result of it does not change:

Ammonium carbonate decomposes when heated on carbon dioxide, water and ammonia. The reaction is not redox:

Ammonium nitrate decomposes on nitrogen oxide (I) and water. The reaction refers to ORP:

Task number 27.

From the proposed list, select two external exposure, which lead to an increase in the reaction rate of nitrogen with hydrogen.

1) temperature decrease

2) Increased pressure in the system

5) the use of an inhibitor

Write down in the response field of the number of selected external influences.

Answer: 24.

Explanation:

1) temperature decrease:

The speed of any reaction when the temperature decreases decreases

2) Increased pressure in the system:

Increased pressure increases the speed of any reaction in which at least one gaseous substance takes part.

3) decrease in hydrogen concentration

Reducing the concentration always reduces the reaction rate

4) an increase in nitrogen concentration

An increase in the concentration of reagents always increases the reaction rate

5) the use of an inhibitor

Inhibitors call substances that slow down the reaction rate.

Task №22.

Install the correspondence between the formula of the substance and electrolysis products aquatic solution This substance on the inert electrodes: to each position indicated by the letter, select the appropriate position indicated by the number.

Write in the table selected numbers under the appropriate letters.

BUT	B.	IN	G.

Answer: 5251.

Explanation:

A) Nabr → Na + + Br -

Cathiode among themselves compete Na + cations and water molecules.

2H 2 O + 2E - → H 2 + 2OH -

2CL - -2E → Cl 2

B) Mg (NO 3) 2 → MG 2+ + 2NO 3 -

Cathiode among themselves compete mg 2+ cations and water molecules.

Cations alkali metalsAs well as magnesium and aluminum are not capable of recovering in aqueous solution due to high activity. For this reason, water molecules are restored instead of them in accordance with equation:

2H 2 O + 2E - → H 2 + 2OH -

Anions NO 3 and water molecules compete with each other.

2H 2 O - 4E - → O 2 + 4H +

Thus, response 2 (hydrogen and oxygen) is suitable.

C) ALCL 3 → AL 3+ + 3CL -

Alkali metal cations, as well as magnesium and aluminum are not capable of recovering under aqueous solution conditions due to high activity. For this reason, water molecules are restored instead of them in accordance with equation:

2H 2 O + 2E - → H 2 + 2OH -

The anions cl - and water molecules compete with each other.

Anions consisting of one chemical element (except F -) won competition in water molecules for oxidation on the anode:

2CL - -2E → Cl 2

This suits the answer option 5 (hydrogen and halogen).

D) Cuso 4 → Cu 2+ + SO 4 2-

Metal cations The right of hydrogen in a row of activity is easily restored under an aqueous solution:

Cu 2+ + 2e → Cu 0

Acid residues containing acid-forming element in the highest oxidation, lose competition of water molecules for oxidation on the anode:

2H 2 O - 4E - → O 2 + 4H +

This suits the option of response 1 (oxygen and metal).

Task number 23.

Set the correspondence between the name of the salt and the aqueous solution of this salt: to each position indicated by the letter, select the corresponding position indicated by the number.

Write in the table selected numbers under the appropriate letters.

BUT	B.	IN	G.

Answer: 3312.

Explanation:

A) iron sulfate (III) - Fe 2 (SO 4) 3

educated weak "base" Fe (OH) 3 and a strong acid H 2 SO 4. Conclusion - sour Wednesday

B) chromium chloride (III) - CRCL 3

it is formed by the weak "base" CR (OH) 3 and a strong acid HCl. Conclusion - sour Wednesday

C) sodium sulfate - Na 2 SO 4

Formed by a strong base of NaOH and a strong acid H 2 SO 4. Conclusion - Neutral medium

D) sodium sulphide - na 2 s

Educated by a strong base of NaOH and weak acid H 2 S. Conclusion - alkaline medium.

Task number 24.

Set the correspondence between the way of exposure to the equilibrium system

Co (g) + Cl 2 (g) COCL 2 (g) + Q

and the direction of displacement chemical equilibrium As a result of this impact: to each position indicated by the letter, select the appropriate position indicated by the number.

Write in the table selected numbers under the appropriate letters.

BUT	B.	IN	G.

Answer: 3113.

Explanation:

The displacement of equilibrium with external exposure to the system occurs in such a way as to minimize the effect of this external influence (the principle of Le Chatel).

A) an increase in the concentration of CO leads to a displacement of equilibrium towards a direct reaction, since as a result of it, the amount of CO decreases.

B) The temperature increase will shift the equilibrium towards the endothermic reaction. Since the direct reaction is exothermic (+ q), then the equilibrium will be shifted towards the reverse reaction.

C) reduction of pressure will shift equilibrium towards the reaction as a result of which an increase in the amount of gases occurs. As a result of the reverse reaction, more gases are formed than as a result of direct. Thus, the equilibrium will shift towards the reverse reaction.

D) an increase in chlorine concentration leads to a displacement of equilibrium towards a direct reaction, since as a result of it, the amount of chlorine is reduced.

Task №25

Set the correspondence between the two substances and the reagent, with which you can distinguish between these substances: to each position indicated by the letter, select the appropriate position indicated by the number.

Answer: 3454.

Explanation:

You can distinguish two substances with the help of the third only if these two substances interact with it differently, and, most importantly, these differences are extremely distinguishable.

A) FESO 4 and FECL 2 solutions can be distinguished using a barium nitrate solution. In the case of FESO 4, the formation of a white precipitate of barium sulfate:

FESO 4 + BACL 2 \u003d BASO 4 ↓ + FECL 2

In the case of FECL 2, there is no visible signs of interaction, since the reaction does not proceed.

B) Na 3 PO 4 and Na 2 SO 4 solutions can be distinguished using the MGCl 2 solution. The solution of Na 2 SO 4 does not enter the reaction, and in the case of Na 3 PO 4, a white precipitate of magnesium phosphate falls:

2NA 3 PO 4 + 3MGCl 2 \u003d Mg 3 (PO 4) 2 ↓ + 6NACL

C) KOH and CA (OH) 2 solutions can be distinguished by the solution of Na 2 CO 3. KOH with Na 2 CO 3 does not react, and Ca (OH) 2 gives with Na 2 CO 3 white calcium carbonate precipitate:

Ca (OH) 2 + Na 2 CO 3 \u003d Caco 3 ↓ + 2NAOH

D) Kon and KCL solutions can be distinguished by the MGCl 2 solution. KCl with MgCl 2 does not react, and the mixing of solutions of Kon and MgCl 2 leads to the formation of a white precipitate of magnesium hydroxide:

MgCl 2 + 2Kone \u003d Mg (OH) 2 ↓ + 2KCL

Task number 26.

Install the correspondence between the substance and the application area: to each position indicated by the letter, select the appropriate position indicated by the number.

Write in the table selected numbers under the appropriate letters.

BUT	B.	IN	G.

Answer: 2331.

Explanation:

Ammonia - used in the production of nitrogen fertilizers. In particular, ammonia is a raw material for production nitric acidFrom which, in turn, fertilizers are obtained - sodium, potassium and ammonium nitrates (Nano 3, Kno 3, NH 4 NO 3).

Carbon tetrachloride and acetone are used as solvents.

Ethylene is used to obtain high molecular weight compounds (polymers), namely polyethylene.

The answer to the tasks 27-29 is the number. Record this number in the response field in the text of the work, while observing the specified degree of accuracy. Then transfer this number to the response form No. 1 to the right of the number of the corresponding task, starting from the first cell. Each character is written in a separate cell in accordance with the samples given in the form. Units physical quantities No need to write.

Task number 27.

What kind of potassium hydroxide should be dissolved in 150 g of water to obtain a solution with a mass fraction of a 25%? (Record the number up to the integer.)

Answer: 50.

Explanation:

Let the mass of potassium hydroxide, which must be dissolved in 150 g of water, is X g. Then the mass of the resulting solution will be (150 + x) r, and a mass fraction of alkali in such a solution can be expressed as X / (150 + x). From the condition, we know that the mass fraction of potassium hydroxide is 0.25 (or 25%). Thus, the equation is true:

x / (150 + x) \u003d 0.25

Thus, the mass that must be dissolved in 150 g of water to obtain a solution with a mass fraction of 25% is 50 g.

Task №28.

To the reaction, the thermochemical equation of which

MGO (TV.) + CO 2 (g) → MGCO 3 (TV.) + 102 kJ,

88 g of carbon dioxide entered. What amount of heat is highlighted at the same time? (Record the number up to the integer.)

Answer: ___________________________ KJ.

Answer: 204.

Explanation:

Calculate the amount of carbon dioxide substance:

n (CO 2) \u003d N (CO 2) / M (CO 2) \u003d 88/44 \u003d 2 mole,

According to the reaction equation, the interaction of 1 mol CO 2 with magnesium oxide is released 102 kJ. In our case, the amount of carbon dioxide is 2 mol. Denote by the amount of heat released at the same time as X KJ, you can write down the following proportion:

1 mol CO 2 - 102 kJ

2 mol CO 2 - X KJ

Consequently, the equation is true:

1 ∙ x \u003d 2 ∙ 102

Thus, the amount of heat that is extended with the participation in the reaction with magnesium oxide 88 g of carbon dioxide is 204 kJ.

Task number 29.

Determine the mass of zinc, which reacts with hydrochloric acid to produce 2.24 liters (N.O.) of hydrogen. (Record the number up to the tenths.)

Answer: ___________________________

Answer: 6.5

Explanation:

We write the reaction equation:

Zn + 2HCl \u003d ZnCl 2 + H 2

Calculate the amount of hydrogen substance:

n (H 2) \u003d V (H 2) / V m \u003d 2.24 / 22.4 \u003d 0.1 mol.

Since there are equal coefficients in the reaction equation in front of zinc and hydrogen, this means that the amounts of zinc substances entered into the reaction and hydrogen formed as a result of it are also equal, i.e.

n (zn) \u003d n (H 2) \u003d 0.1 mol, therefore:

m (zn) \u003d n (zn) ∙ m (zn) \u003d 0.1 ∙ 65 \u003d 6.5 g

Do not forget to transfer all the answers to the answer blank number 1 in accordance with the instructions for performing the work.

Task number 33.

Sodium bicarbonate weighing 43.34 g was performed to constant mass. The residue was dissolved in the excess of hydrochloric acid. The resulting gas was missed through 100 g of a 10% sodium hydroxide solution. Determine the composition and mass of the resulting salt, its mass fraction in solution. In response, write down the reaction equations that are specified in the task condition, and give all the necessary calculations (specify the units of measurement of the desired physical quantities).

Answer:

Explanation:

Sodium bicarbonate when heated is decomposed in accordance with the equation:

2NAHCO 3 → Na 2 CO 3 + CO 2 + H 2 O (I)

The resulting solid residue obviously consists only of sodium carbonate. When dissolving sodium carbonate in hydrochloric acid Next reaction flows:

Na 2 CO 3 + 2HCl → 2NACL + CO 2 + H 2 O (II)

Calculated the amount of substance of sodium bicarbonate and sodium carbonate:

n (NaHCO 3) \u003d M (NaHCO 3) / M (NaHCO 3) \u003d 43.34 g / 84 g / mol ≈ 0.516 mol,

hence,

n (Na 2 CO 3) \u003d 0.516 mol / 2 \u003d 0.258 mol.

Calculate the amount of carbon dioxide formed by reaction (II):

n (CO 2) \u003d N (Na 2 CO 3) \u003d 0.258 mol.

We calculate the mass of pure sodium hydroxide and its amount of the substance:

m (NaOH) \u003d m p-ra (NaOH) ∙ Ω (NaOH) / 100% \u003d 100 g ∙ 10% / 100% \u003d 10 g;

n (NaOH) \u003d M (NaOH) / M (NaOH) \u003d 10/40 \u003d 0.25 mol.

The interaction of carbon dioxide with sodium hydroxide, depending on their proportions, may occur in accordance with two different equations:

2NAOH + CO 2 \u003d Na 2 CO 3 + H 2 O (with an excess of alkali)

NaOH + CO 2 \u003d NaHCO 3 (with an excess of carbon dioxide)

From the presented equations, it follows that only the average salt is obtained with the ratio N (NaOH) / N (CO 2) ≥2, and only acid, with a ratio N (NaOH) / N (CO 2) ≤ 1.

According to calculations ν (CO 2)\u003e ν (NaOH), therefore:

n (NaOH) / N (CO 2) ≤ 1

Those. The interaction of carbon dioxide with sodium hydroxide occurs solely to the formation of acid salt, i.e. In accordance with equation:

NaOH + CO 2 \u003d NaHCO 3 (III)

Calculation is carried out on shortness of alkali. By the reaction equation (III):

n (NaHCO 3) \u003d n (NaOH) \u003d 0.25 mol, therefore:

m (NaHCO 3) \u003d 0.25 mol ∙ 84 g / mol \u003d 21 g

The mass of the resulting solution will fold from the mass of the alkali solution and the mass of carbon dioxide absorbed by it.

From the reaction equation, it follows that reacted, i.e. Miselid only 0.25 mol CO 2 of 0.258 mol. Then the mass of the absorbed CO 2 is:

m (CO 2) \u003d 0.25 mol ∙ 44 g / mol \u003d 11 g

Then, the solution of the solution is equal to:

m (p-ra) \u003d m (p-ra NaOH) + m (CO 2) \u003d 100 g + 11 g \u003d 111 g,

a mass fraction of sodium bicarbonate in the solution will thus be equal to:

ω (NaHCO 3) \u003d 21 g / 111 g ∙ 100% ≈ 18.92%.

Task number 34.

When combustion 16.2 g organic The non-cyclic structure was obtained 26.88 l (N.U.) carbon dioxide and 16.2 g of water. It is known that 1 mol of this organic matter in the presence of the catalyst attaches only 1 mol of water and this substance does not react with the ammonia solution of silver oxide.

On the basis of these conditions of the problem:

1) Calculates needed to establish the molecular formula of the organic matter;

2) write down the molecular formula of the organic matter;

3) make a structural formula of an organic matter, which uniquely reflects the order of communication of atoms in its molecule;

4) Write an organic substance hydration reaction equation.

Answer:

Explanation:

1) To determine the elemental composition, calculate the amount of carbon dioxide, water, and then the masses of the elements included in them:

n (CO 2) \u003d 26.88 l / 22.4 l / mol \u003d 1.2 mol;

n (CO 2) \u003d n (C) \u003d 1.2 mol; M (C) \u003d 1.2 mol ∙ 12 g / mol \u003d 14.4 g.

n (H 2 O) \u003d 16.2 g / 18 g / mol \u003d 0.9 mol; n (h) \u003d 0.9 mol ∙ 2 \u003d 1.8 mol; M (H) \u003d 1.8 g

m (Org. V-Ba) \u003d M (C) + M (H) \u003d 16.2 g, therefore, there is no oxygen in the organic substance.

The general formula of the organic compound is C x H y.

x: y \u003d ν (c): ν (H) \u003d 1,2: 1, 8 \u003d 1: 1,5 \u003d 2: 3 \u003d 4: 6

Thus, the simplest formula of the substance C 4 H 6. The true formula can substance can coincide with the simplest, and may differ from it for an integer time. Those. Be, for example, with 8 H 12, with 12 H 18, etc.

The condition states that the hydrocarbon is non-cyclic and one of its molecule can attach only one water molecule. This is possible if there is only one multiple communication (double or triple) in the structural formula of substance. Since the desired hydrocarbon is non-cyclic, it is obvious that one multiple bond can only be for a substance with a C 4 H 6 formula. In the case of other hydrocarbons with a greater molecular weight, the number of multiple connections is more than one everywhere. Thus, the molecular formula of the substance C 4 H 6 coincides with the simplest.

2) The molecular formula of the organic matter is C 4 H 6.

3) Alkins interact from hydrocarbons with ammonia solution of silver oxide, in which the triple bond is located at the end of the molecule. In order for the interaction with ammonia solution of silver oxide, alkin of the C 4 H 6 composition should be the following structure:

CH 3 -C≡C-CH 3

4) Alkin hydration proceeds in the presence of bivalent mercury salts.

The examination option in this publication was proposed to graduates in early eME on history on March 20, 2017

On the content of Kima, we can say the following:

In tasks 1-2, the content is usual, without surprises, except for the mention of Ipatiev chronicles. As a rule, there is no such concretization.

In task 3, in my opinion, the terms associated with the XVIII century began to appear very often. Maybe this is a subjective look, but somehow it seems that other periods are undervalued in this regard.

The term in the fourth, on the contrary, rather non-bank. It is worth identifying numerous purchases, orders and other tyunov with flames. But not long, but even at night they dream together with some governor, chargeting with you a virgin :)

5-7 tasks are quite normal, nothing special.

Here in the 8th question about the scout, perhaps surprised. An unusual character for tasks, although it seems to be R. Zorga somewhere came across.

In the 9th, nothing complicated, but in the 10th I would carefully read into the text. An uneteced question, but it seems that the compiler has tried very much when wording the question of disguise the name of the Soviet government. Ears, however, stick out anyway :)

The 11th task without surprises, but the 12th forces the second time to think about what, perhaps, was the task of a specialist in the history of Russia until the XIX century.

Tasks 13-16 in the Great Patriotic War - alas, this is one of the worst options with the map, and they forgive me all the fans of this period. It can only be the events of civilian / "cold" wars or economics.

The 17th culture is normal, especially if you watched, see or watch a piggy banks of Cat Stepan :)

Download piggy banks for illustrations

The 18th will not be difficult, like any image of a similar popular format (brand, coins), if you carefully consider and read the proposed options. The 19th task is also not difficult, all personalities are more than known.

As for the tasks of the second part, the 20-21 will not cause difficulties, but 22 should be carefully examined and not to rush with the answer, which, at the same time, literally on the surface.

Task 23 Once again proves that the solutions of the main congresses of the Bolshevik Party need to know (see)

The 24th task for arguments creates a steady dejum that Alexander III has become simply just before indecency. So, for example, in the last Statgradian training from April (2017), there was a task about his internal politics.

The choice of periods for the essay disappointed. The first and last, besides, crosswise, which in itself makes them complex. Part of the period of the Board of Nicholas II in the second version also does not improve the picture.

In general, it is good here that this option will not come to anyone.

Download early option

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